A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}-C(OH)=CHOH\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: D
Solution :
Key Idea: \[{{\text{H}}_{\text{2}}}\text{O}\]adds across triple bond in presence of \[\text{H}{{\text{g}}^{2+}}\]salt. \[\underset{\text{propyne}-1}{\mathop{C{{H}_{3}}-C}}\,\equiv CH+{{H}_{2}}O\xrightarrow{{{H}^{+}}/H{{g}^{2+}}}\] \[C{{H}_{3}}-\overset{O}{\mathop{\underset{\text{acetone}}{\overset{||}{\mathop{C}}}\,}}\,-C{{H}_{3}}\]
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