A) 3-oxo-butanoic acid
B) 4-oxo-propanoic acid
C) 3-formyl-propanoic acid
D) none of the above
Correct Answer: C
Solution :
Key Idea: If the organic compound has two groups having C atom placed at ends of carbon chain, only the carbon of group of higher priority is included in chain. \[\underset{3-\text{formyl}\,\text{propanoic}\,\text{acid}}{\mathop{H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\overset{3}{\mathop{C}}\,{{H}_{2}}-\overset{2}{\mathop{C}}\,{{H}_{2}}-\overset{1}{\mathop{C}}\,OOH}}\,\]
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