A) \[0.13\text{ }m/{{s}^{2}}\]
B) \[~0.16\text{ }m/{{s}^{2}}\]
C) \[~0.18\text{ m/}{{\text{s}}^{2}}\]
D) \[~0.34\text{ }m/{{s}^{2}}\]
Correct Answer: A
Solution :
The distance travelled by the body in nth second is given by \[{{s}_{n}}=u+\frac{1}{2}a(2n-1)\] ?(I ) Since, body starts from rest, so \[u=0.\] Given, \[{{s}_{n}}=110\,cm,\,n=9\] Substituting the values in Eq. (i), we get \[110=0+\frac{1}{2}a(2\times 9-1)\] or \[110=\frac{a}{2}\times 17\] \[\therefore \] \[a=\frac{2\times 110}{17}\approx 13\,cm/{{s}^{2}}\] or \[a=0.13\,m/{{s}^{2}}\]
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