A) 600 mL
B) 300 mL
C) 500 mL
D) 200 Ml
Correct Answer: C
Solution :
Key Idea: Use the following formula to find volume of NaOH. \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] Given, \[{{N}_{1}}=\]normality of\[NaOH=0.4\,M\] \[{{V}_{1}}=\] volume of\[\text{ }\!\!~\!\!\text{ NaOH}\,\text{=}\]? \[{{N}_{2}}=\]normality of \[{{H}_{2}}S{{O}_{4}}=0.5\,M\,{{H}_{2}}S{{O}_{4}}\] \[{{V}_{2}}=\]volume of \[{{H}_{2}}S{{O}_{4}}=200\,mL\] \[\therefore \] \[0.4\times {{V}_{1}}=(2\times 0.5)\times 200\] (\[\because \,\]it is diprotic acid) or \[{{V}_{1}}=\frac{2\times 0.5\times 200}{0.4}\] \[=500\,mL\]
You need to login to perform this action.
You will be redirected in
3 sec
