A) \[4.2\times {{10}^{7}}cal/K\]
B) \[4.2\,cal/K\]
C) \[8.31\,cal/K\]
D) \[2\,cal/K\]
Correct Answer: D
Solution :
Key Idea: According to ideal gas equation \[\frac{PV}{T}=R\] where R = gas constant Value of R for 1 mole of gas \[=8.31\text{ }J/mol\text{ }K\] \[=\,1.987\approx 2cal/K\]
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