A) \[{{L}^{6}}\]
B) \[{{M}^{1}}{{L}^{-1}}{{T}^{-2}}\]
C) \[{{M}^{1}}{{L}^{5}}{{T}^{-2}}\]
D) \[{{L}^{3}}\]
Correct Answer: C
Solution :
\[\left( P+\frac{a}{{{V}^{2}}} \right)(V-b)=RT\] Dimensional formula of \[a=\]Dimensions of \[P\times \]dimensions of \[{{V}^{2}}\] \[=[M{{L}^{-1}}{{T}^{-2}}][{{L}^{6}}]\] \[=[M{{L}^{5}}{{T}^{-2}}]\]
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