A) \[150\,N{{C}^{-1}}\]
B) \[250\,N{{C}^{-1}}\]
C) \[60\,N{{C}^{-1}}\]
D) \[35\,N{{C}^{-1}}\]
Correct Answer: B
Solution :
Electric field \[\vec{E}\]in broad side-on position is \[\vec{E}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{P}{{{r}^{3}}}\] where p is dipole moment given by \[p=q\times 2l=(3\times {{10}^{-6}}C)(2\times {{10}^{-3}}m)\] \[=6\times {{10}^{-9}}C-m\] Hence, \[\vec{E}=9\times {{10}^{9}}\times \frac{6\times {{10}^{-9}}}{{{(0.6)}^{3}}}=250N{{C}^{-1}}\]
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