A) \[\text{0}\text{.60 A}{{\text{m}}^{\text{2}}}\]
B) \[~0.45\text{ A}{{\text{m}}^{2}}\]
C) \[\text{ }\!\!~\!\!\text{ 0}\text{.30 A}{{\text{m}}^{\text{2}}}\]
D) \[~0.15A{{m}^{2}}\]
Correct Answer: C
Solution :
Magnetic dipole moment of a current carrying circular coil is given by \[M=Ni\,A=Ni\,\pi \,{{r}^{2}}\] Given, \[N=20,\,i=3A,\,\,r=4\,cm=0.0\,4\,m\] \[\therefore \] \[M=20\times 3\times 3.14\times {{(0.04)}^{2}}\] \[\Rightarrow \] \[M=0.3\,A-{{m}^{2}}\]
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