A) \[N{{H}_{3}}\]
B) \[{{N}_{3}}H\]
C) \[{{N}_{2}}{{H}_{4}}\]
D) \[{{N}_{2}}\]
Correct Answer: B
Solution :
\[N{{H}_{4}}OH+F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}{{N}_{3}}H\].
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