A) \[C{{u}_{4}}A{{g}_{4}}Au\]
B) \[CuA{{g}_{3}}Au\]
C) \[CuAgCu\]
D) \[C{{u}_{4}}A{{g}_{2}}Cu\]
Correct Answer: B
Solution :
\[Cu\]atoms are at eight comers of the cube. Therefore, the number of Cu atoms in the unit cell \[=\frac{8}{8}=1\] \[Au\] atoms are at the face-centre of six faces. Therefore, its share in the unit cell\[=\frac{6}{2}=3\] At atoms are at the body centres, so the number of \[Au\] atom\[=1\] \[\therefore \]The formula of the alloy is\[CuA{{g}_{3}}Au\].
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