A) boron
B) metaboric acid
C) boric anhydride
D) borax
Correct Answer: C
Solution :
\[\underset{Ortho\,\,boric\,\,acid}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,\underset{Above\,\,370\,\,K}{\mathop{\xrightarrow{\Delta }}}\,\underset{Metaboric\,\,acid}{\mathop{HBO}}\,\]\[\xrightarrow{\Delta }\underset{Boric\,\,anhydride}{\mathop{{{B}_{2}}{{O}_{3}}}}\,\]
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