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JCECE Engineering JCECE Engineering Solved Paper-2015

  • question_answer
    One mole of an ideal gas is taken from state \[P\] to state \[Q\] by three different processes (i)\[PRQ\], (ii) \[PSQ\] and (iii) \[PTQ\] as shown in the \[p-V\] diagram. The heat absorbed by the gas is

    A)  the least in process (ii)

    B)  greater in process (ii) than in process (i)

    C)  the same in the processes (i) and (iii)

    D)   less in process (iii) than in process (ii)

    Correct Answer: D

    Solution :

    Heat absorbed by gas in three processes can be written as                 \[\Delta {{Q}_{PRQ}}=\Delta U+{{W}_{PRQ}}\]                 \[\Delta {{Q}_{PSQ}}=\Delta U\]                 \[\Delta {{Q}_{PTQ}}=\Delta U+{{W}_{PTQ}}\] The change in internal energy in all the three cases is same and\[\Delta {{W}_{PRQ}}>0,\,\,\Delta {{W}_{PTQ}}<0\] Hence,  \[\Delta {{Q}_{PRQ}}>\Delta {{Q}_{PSQ}}>\Delta {{Q}_{PTQ}}\]


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