A) \[2\pi (\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S\]
B) \[\pi ({{a}_{1}}+{{b}_{1}}+{{a}_{2}}+{{b}_{2}})S\]
C) \[\pi \left( \frac{{{a}_{1}}+{{a}_{2}}}{2}+\frac{{{b}_{1}}+{{b}_{2}}}{2} \right)S\]
D) \[\sqrt{2}\pi (\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S\]
Correct Answer: A
Solution :
Internal mean radius\[{{r}_{1}}=\sqrt{{{a}_{1}}{{b}_{1}}}\] Internal circumference of the ring \[=2\pi {{r}_{1}}=2\pi \sqrt{{{a}_{1}}{{b}_{1}}}\] External mean radius\[{{r}_{2}}=\sqrt{{{a}_{2}}{{b}_{2}}}\] External circumference of the ring \[=2\pi {{r}_{2}}=2\pi \sqrt{{{a}_{2}}{{b}_{2}}}\] Thus, force required \[=2\pi \sqrt{{{a}_{1}}{{b}_{1}}}S+2\pi \sqrt{{{a}_{2}}{{b}_{2}}}S\] \[=2\pi (\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S\]
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