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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    Which particle among the following will have the smallest de-Broglie wavelength, assuming that they have the same velocity?

    A)  A positron                         

    B)  A photon

    C)   An \[\alpha -\]particle                

    D)   A neutron

    Correct Answer: C

    Solution :

    The de-Broglie equation is\[\lambda =\frac{h}{p}=\frac{h}{mv}\]. Here, \[h\] and \[v\] are constant. So\[,\,\,\lambda \propto \frac{1}{m}\]. Since, the \[\alpha -\]particle has the highest mass among the given entities, it has the smallest de-Broglie wavelength.


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