question_answer

\[{{C}_{6}}{{H}_{6}}+C{{l}_{2}}(excess)\xrightarrow[dark,\,cold]{Anhy.\,AlC{{l}_{8}}}P\]Product, \[P\] is

A) \[{{C}_{6}}{{H}_{5}}Cl\]                

B) \[{{C}_{6}}{{H}_{4}}C{{l}_{2}}\]

C) \[{{C}_{6}}{{H}_{6}}C{{l}_{6}}\]                 

D)  \[{{C}_{6}}C{{l}_{6}}\]

Correct Answer: D

Solution :

Benzene on treatment with excess of chlorine in the presence of anhydrous \[AlC{{l}_{3}}\] in dark yields hexachlorobenzene.