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JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    \[C{{H}_{3}}-C\equiv CH\xrightarrow[1%HgS{{O}_{4}}]{40%{{H}_{2}}S{{O}_{4}}}a\xrightarrow{Isomerisation}\] Structure of \[A\] and the type of isomerism in the above reaction are respectively.

    A)  prop-1-en-2-ol, metamerism

    B)  prop-1-en-1-ol, tautomerism

    C)  prop-2-en-2-ol, \[cis\] and trans isomerism

    D)   prop-2-en-1-ol, tautomerism

    Correct Answer: B

    Solution :

    \[C{{H}_{3}}-C\equiv CH\xrightarrow[1%\,\,HgS{{O}_{4}}]{40%\,\,{{H}_{2}}S{{O}_{4}}}\underset{prop-1-en-2-ol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,\]\[\xrightarrow{Tautomerisation}C{{H}_{3}}COC{{H}_{3}}\]


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