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JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    \[4L\] of \[0.02\,\,M\] aqueous solution of \[NaCl\] was diluted by adding \[1\,\,L\] of water. The molality of the resultant solution is

    A) \[0.004\]                             

    B) \[0.008\]

    C)  \[0.012\]                            

    D)  \[0.016\]

    Correct Answer: D

    Solution :

    \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\]or       \[0.02\times 4={{M}_{2}}\times 5\]or     \[{{M}_{2}}=0.016\]


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