JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    Bond dissociation enthalpy of \[E-H(E=\] element) bonds is given below. Which of the compounds will act as strongest reducing agent? Compound                     \[=\]\[N{{H}_{3}}\]             \[P{{H}_{3}}\]    \[As{{H}_{3}}\]  \[Sb{{H}_{3}}\] \[{{\Delta }_{diss(E-H)(kJmo{{l}^{-1}})}}=\]\[389\]            \[322\]  \[297\]  \[255\]

    A) \[N{{H}_{3}}\]                                  

    B) \[P{{H}_{3}}\]

    C) \[As{{H}_{3}}\]                 

    D)  \[Sb{{H}_{3}}\]

    Correct Answer: D

    Solution :

    Weaker the \[E-H\] bond, stronger the reducing agent\[i.e.,\,\,Sb{{H}_{3}}\].


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