JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    A plane electromagnetic wave propagating in \[x\,\,(-)\]direction as a wave function (in \[SI\] units) is given as \[\psi (x,\,\,t)={{10}^{3}}\sin \pi (3\times {{10}^{6}}x-9\times {{10}^{14}}t)\] The speed of the wave is

    A) \[3\times {{10}^{6}}m/s\]                           

    B) \[3\times {{10}^{7}}m/s\]

    C) \[3\times {{10}^{8}}m/s\]                           

    D) \[9\times {{10}^{14}}m/s\]

    Correct Answer: C

    Solution :

    Comparing the given equation of wave with\[y=a\sin \left( \frac{2\pi }{\lambda }x-\frac{2\pi }{T}t \right)\], we have                 \[\frac{2\pi }{\lambda }=\pi \times 3\times {{10}^{6}}\] or            \[\lambda =\frac{2}{3\times {{10}^{6}}}m\] and        \[\frac{2\lambda }{T}=\pi \times 9\times {{10}^{14}}\] or            \[v=\frac{1}{T}=\frac{9}{2}\times {{10}^{14}}Hz\] \[\therefore \]Speed of wave,                 \[c=v\lambda =\frac{(9\times {{10}^{14}})}{2}\times \frac{2}{(3\times {{10}^{6}})}\]                    \[=3\times {{10}^{8}}m/s\]


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