A) \[30\,\,N\]
B) \[40\,\,N\]
C) \[72\,\,N\]
D) \[400\,\,N\]
Correct Answer: C
Solution :
Given,\[{{m}_{2}}=10\,\,kg;\,\,{{m}_{1}}=30\,\,g,\,\,{{v}_{1}}=400\,\,m/s\] Number of bullets fired/second\[=6\] \[F=?\] We know, \[F=\]rate of change of .linear momentum \[\therefore \] \[F=\frac{change\,\,in\,\,linear\,\,momentum}{time}\] In\[t=1s,\]total mass of bullets fired \[=30\times 6=180\,\,g\] \[=180\times {{10}^{-3}}kg\] So, \[F=\frac{180\times {{10}^{-3}}\times 400}{1}\] \[=72\,\,N\]
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