A) \[25\Omega \]
B) \[10\Omega \]
C) \[5\Omega \]
D) None of these
Correct Answer: C
Solution :
Here \[4\Omega \] and \[12\Omega \] are in parallel. \[\therefore \] \[\frac{1}{R}=\frac{1}{4}+\frac{1}{12}\] \[\Rightarrow \] \[R=\frac{4\times 12}{4+12}=3\Omega \] Similarly, \[6\Omega \] and \[3\Omega \] are in parallel. \[\therefore \] \[\frac{1}{R'}=\frac{1}{6}+\frac{1}{3}\] \[\Rightarrow \] \[R'=\frac{6\times 3}{6+3}=2\Omega \] \[R\] and \[R'\] are in series. \[\therefore \]Equivalent resistance between \[A\] and \[B\] \[R''=R+R'=3+2=5\Omega \]
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