A) \[300\,\,\min \]
B) \[360\,\,\min \]
C) \[398.8\,\,\min \]
D) \[400\,\,\min \]
Correct Answer: C
Solution :
\[t=\frac{2.303}{k}\log \frac{a}{a-x}\] (I) When\[a=100\],\[x=50\]and\[t=120\min \] \[k=\frac{2.303}{120}\log \frac{100}{100-50}\] \[k=\frac{2.303}{120}\log 2\] \[k=\frac{2.303\times 0.3010}{120}=0.00578\,\,{{\min }^{-1}}\] (II) When\[a=100\],\[x=90\],\[t=?\] \[t=\frac{2.303}{0.00578}\log \frac{100}{100-90}\] \[t=\frac{2.303}{0.00578}\times \log 10=398.4\approx 398.8min\]
You need to login to perform this action.
You will be redirected in
3 sec
