A) \[0.8\,\,M\]
B) \[0.6\,\,M\]
C) \[0.4\,\,M\]
D) \[0.2\,\,M\]
Correct Answer: B
Solution :
\[\underset{Initial}{\mathop{{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}}}\,=\underset{Final}{\mathop{{{M}_{3}}{{V}_{3}}}}\,\] \[{{V}_{3}}={{V}_{1}}+{{V}_{2}}=800+200=1000\,\,mL\] \[=0.5\times 800+1\times 200={{M}_{3}}\times 1000\] \[{{M}_{3}}=\frac{600}{1000}=0.6\,\,M\]
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