A) \[50\Omega \]
B) \[60\Omega \]
C) \[90\Omega \]
D) \[120\Omega \]
Correct Answer: B
Solution :
Current through inductance,\[{{i}_{L}}=\frac{90}{30}=3\,\,A\] Current through capacitor,\[{{i}_{C}}=\frac{90}{20}=4.5\,\,A\] Net current through circuit \[i={{i}_{C}}-{{i}_{L}}=4.5-3=1.5\,\,A\] \[\therefore \]Impedance of the circuit, \[Z=\frac{V}{i}=\frac{90}{1.5}=60\Omega \]
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