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JCECE Engineering JCECE Engineering Solved Paper-2012

  • question_answer
    The radius of two metallic spheres \[A\] and \[B\] are \[{{r}_{1}}\] and \[{{r}_{2}}\] respectively\[({{r}_{1}}>{{r}_{2}})\]. They are connected by a thin wire and the system is given a certain charge. The charge will be greater

    A)  equal on both

    B)  zero on both

    C)  on the surface of sphere\[A\]

    D)   on the surface of sphere\[B\]

    Correct Answer: C

    Solution :

    When the spheres are connected by a wire, then potential on both becomes equal. \[\therefore \]  \[\frac{{{Q}_{1}}}{{{r}_{1}}}=\frac{{{Q}_{2}}}{{{r}_{2}}}\]    \[\Rightarrow \]     \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\]when\[{{r}_{1}}>{{r}_{2}}\], then\[{{Q}_{1}}>{{Q}_{2}}\]


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