A) \[220\,\,V\]
B) \[110\,\,V\]
C) \[311.1\,\,V\]
D) \[\frac{220}{\sqrt{2}}V\]
Correct Answer: D
Solution :
The diode \[D\] will conduct for positive half cycle of \[AC\] supply because this is forward biased. For negative half cycle of \[AC\] supply, this is reverse biased and does not conduct. So output would be half wave rectified and for half wave rectified output will \[{{V}_{rms}}=\frac{{{V}_{0}}}{2}=\frac{220\sqrt{2}}{2}=\frac{220}{\sqrt{2}}\]
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