A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{2}\]
D) \[\frac{\pi }{6}\]
Correct Answer: C
Solution :
We have,\[\frac{2\cos A}{a}+\frac{2\cos B}{b}+\frac{2\cos C}{C}=\frac{a}{bc}+\frac{b}{ac}\] \[\Rightarrow \] \[2\left( \frac{{{b}^{2}}+{{c}^{2}}-{{a}^{2}}}{2abc} \right)+\frac{{{c}^{2}}+{{a}^{2}}-{{b}^{2}}}{2abc}\] \[+2\left( \frac{{{a}^{2}}+{{b}^{2}}-{{c}^{2}}}{2abc} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
