A) copper chloride in water
B) \[NaCl\] in water
C) ferric chloride in water
D) \[AuC{{l}_{3}}\] in water
Correct Answer: B
Solution :
When current is passed in an aqueous solution of\[NaCl\], the following reaction occur at anode and cathode: \[NaCl\xrightarrow{{}}NaC{{l}^{+}}+C{{l}^{-}}\] At anode \[2C{{l}^{-}}\xrightarrow{{}}C{{l}_{2}}+2{{e}^{-}}\] At cathode \[N{{a}^{+}}+{{e}^{-}}\xrightarrow{{}}Na\] \[2{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}{{H}_{2}}\] Since, the deposition potential of \[Na\] is higher, \[{{H}_{2}}\] is evolved at cathode in place of\[Na\].
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