A) \[+ve\Delta H\] and\[+ve\Delta S\]
B) \[-ve\Delta H\]and\[-ve\Delta S\]
C) \[+ve\Delta H\] and\[-ve\Delta S\]
D) \[-ve\Delta H\]and\[+ve\Delta S\]
Correct Answer: C
Solution :
For a process to be spontaneous, AG will be negative. We know that, \[\Delta G=\Delta H-T\Delta S\] If \[\Delta H=+ve\] and\[\Delta S=-ve,\,\,\Delta G\]will be positive at all temperatures. Thus, the process is non-spontaneous.
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