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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    \[250\,\,mL\] of a sodium carbonate solution contains \[2.65\,\,g\] of\[N{{a}_{2}}C{{O}_{3}}\]. If \[10\,\,mL\] of this solution is diluted to\[1\,\,L\], what is the concentration of the resultant solution? (Mol. wt. of\[N{{a}_{2}}C{{O}_{3}}=106)\]

    A) \[0.1\,\,M\]                       

    B) \[0.001\,\,M\]

    C) \[0.01\,\,M\]                    

    D) \[{{10}^{-4}}M\]

    Correct Answer: B

    Solution :

    Molarity of \[N{{a}_{2}}C{{O}_{3}}\] solution                                 \[=\frac{2.65}{106}\times \frac{1}{250}\times 1000=0.1\,\,M\]                 \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\]                 \[10\times 0.1=1000\times {{M}_{2}}\] \[\therefore \]  \[{{M}_{2}}=\frac{10\times 0.1}{1000}=0.001\,\,M\]


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