A) \[2.5\]
B) \[2.0\]
C) \[1.5\]
D) \[1\]
Correct Answer: B
Solution :
For acid-base reaction, \[\underset{\begin{smallmatrix} (acid) \\ \,\,HCl \end{smallmatrix}}{\mathop{{{N}_{1}}{{V}_{1}}}}\,=\underset{\begin{smallmatrix} (base) \\ NaOH \end{smallmatrix}}{\mathop{{{N}_{2}}{{V}_{2}}}}\,\] \[20\times {{N}_{1}}=40\times 0.005\] \[{{N}_{1}}=0.010=1\times {{10}^{-2}}\] \[pH=-\log [{{H}^{+}}]=-\log (1\times {{10}^{-2}})=2.0\]
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