A) \[{{p}_{1}}>{{p}_{2}}\]
B) \[{{p}_{1}}={{p}_{2}}\]
C) \[{{p}_{1}}<{{p}_{2}}\]
D) \[{{p}_{1}}={{p}_{2}}=0\,\,atm\]
Correct Answer: A
Solution :
\[\pi =iCRT\] \[{{\pi }_{NaCl}}=2\times 0.1\times RT={{p}_{1}}\] \[(i=2\]for\[~NaCl)\] \[{{\pi }_{C{{H}_{3}}COOH}}=1.3\times 0.1\times RT={{p}_{2}}\] \[(i<2\]for \[C{{H}_{3}}COOH\] as it is a weak acid.) \[\Rightarrow \] \[{{p}_{1}}>{{p}_{2}}\]
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