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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    Instantaneous displacement current of \[1.0\,\,A\] in the space between the parallel plates of \[1\,\,\mu F\] capacitor can be established by changing potential difference of

    A) \[{{10}^{-6}}V/s\]                           

    B) \[{{10}^{6}}V/s\]

    C) \[{{10}^{-8}}V/s\]                           

    D)  \[{{10}^{8}}V/s\]

    Correct Answer: B

    Solution :

    \[\frac{Q}{t}=\frac{CV}{t}\] or            \[{{i}_{d}}=C\left( \frac{V}{t} \right)\]                    \[[\because \,\,q=it]\] or            \[\frac{V}{t}=\frac{{{i}_{d}}}{C}=\frac{1}{{{10}^{-6}}}\]                 \[={{10}^{6}}\,\,V/s\]


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