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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    A coil has an area of \[0.05\,\,{{m}^{2}}\] and has \[800\] turns. After placing the coil in a magnetic field of strength \[4\times {{10}^{-5}}Wb{{m}^{-2}}\] perpendicular to the field, the coil is rotated through \[{{90}^{o}}\] in\[0.1\,\,s\]. The average emf induced is

    A) \[zero\]                                               

    B) \[0.016\,\,V\]

    C)  \[0.01\,\,V\]                     

    D)  \[0.032\,\,V\]

    Correct Answer: B

    Solution :

    Induced emf\[e=\frac{d\phi }{dt}=\frac{NAdB}{dt}\]                 \[=800\times 0.05\times \frac{4\times {{10}^{-5}}}{0.1}=0.016\,\,V\]


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