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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    An open pipe of length \[33\,\,cm\] resonates with frequency of\[1000\,\,Hz\]. If the speed of sound is \[333\,\,m{{s}^{-1}}\], then this frequency is

    A)  fundamental frequency of the pipe

    B)  third harmonic of the pipe

    C)   second harmonic of the pipe

    D)   fourth harmonic of the pipe

    Correct Answer: C

    Solution :

    \[1000\,\,Hz=\] Frequency of \[p\text{th}\] harmonic                 \[=\frac{pV}{2l}=\frac{p\times 330}{2\times 33}\]                 \[=\frac{p\times 330\times 100}{2\times 33}\]           \[p=2\]


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