A) \[{{\overset{+}{\mathop{C}}\,}_{2}}{{H}_{5}}\]
B) \[{{(C{{H}_{3}})}_{3}}\overset{+}{\mathop{C}}\,\]
C) \[{{({{C}_{6}}{{H}_{5}})}_{3}}\overset{+}{\mathop{C}}\,\]
D) \[{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,{{H}_{2}}\]
Correct Answer: C
Solution :
\[{{\overset{+}{\mathop{C}}\,}_{2}}{{H}_{5}}\] and\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{{{C}^{\oplus }}}}}\,\]are stabilised by hyperconjugation. In \[{{C}_{6}}{{H}_{5}}\overset{\oplus }{\mathop{C}}\,{{H}_{2}}\] benzyl group is resonance stabilised. In the triphenyl methyl carbonium ion, the \[\pi \] electrons of all the three benzene rings are delocalised with the vacant \[p-\]orbital of central carbon atom. So, it is resonance stabilised. Therefore, it is most stable of the given carbonium ions. More the number ofresonatic structures more will be the stability.
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