JCECE Engineering JCECE Engineering Solved Paper-2010

  • question_answer
    The order of a reaction with rate equal to \[kC_{A}^{3/2}C_{B}^{-1/2}\]is

    A) \[1\]                                     

    B) \[-\frac{1}{2}\]

    C) \[-\frac{3}{2}\]                                 

    D) \[2\]

    Correct Answer: A

    Solution :

    Given,\[r=kC_{A}^{3/2}C_{B}^{-1/2}\] \[\therefore \]  Order of reaction\[=\frac{3}{2}+\left( -\frac{1}{2} \right)\]                                                  \[=\frac{3-1}{2}=1\]


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