JCECE Engineering JCECE Engineering Solved Paper-2009

  • question_answer
    \[0.01\]mole of a non-electrolyte is dissolved in \[10\,\,g\] of water. The molality of the solution is

    A) \[0.1\,\,m\]                       

    B)  \[0.5\,\,m\]

    C)  \[1.0\,\,m\]                      

    D)  \[0.18\,\,m\]

    Correct Answer: C

    Solution :

    Molality\[(m)=\frac{number\,\,of\,\,moles\,\,of\,\,solute}{weight\,\,of\,\,solvent\,\,in\,\,kg}\]                 \[=\frac{0.01}{10\times {{10}^{-3}}}\]                 \[=\frac{0.01\times {{10}^{3}}}{10}\]                 \[=1m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner