A) \[13000\]
B) \[1300\]
C) \[130\]
D) \[13\]
Correct Answer: C
Solution :
\[v=\frac{2}{9}\frac{{{r}^{2}}\rho g}{\eta }\] \[\Rightarrow \] \[\eta =\frac{2}{9}\cdot \frac{{{r}^{2}}\rho g}{v}\] \[=\frac{2}{9}\frac{{{(1\times {{10}^{-2}})}^{2}}\times (1.5\times {{10}^{3}})\times 9.8}{0.25\times {{10}^{-2}}}\]
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