JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    If the planes  \[x+2y+kz=0\] and \[2x+y-2z=0\],are at right angles, then the value of \[k\] is

    A) \[2\]                                     

    B) \[-2\]

    C) \[\frac{1}{2}\]                                   

    D) \[-\frac{1}{2}\]

    Correct Answer: A

    Solution :

    Key Idea If two planes are perpendicular, then the sum of the product of two direction ratios will be zero. Given two planes are                 \[2x+y-2z=0\] and        \[x+2y+kz=0\] Since, two planes are perpendicular, then                 \[{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}+{{c}_{1}}{{c}_{2}}=0\] \[\Rightarrow \]               \[2\cdot 1+1\cdot 2-2(k)=0\] \[\Rightarrow \]               \[-2k+4=0\] \[\Rightarrow \]               \[k=2\]


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