JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    Three forces of magnitude \[30,\,\,\,60\] and \[P\] acting at a point are in equilibrium. If the angle between the first two is\[{{60}^{o}}\], then value of \[P\] is

    A) \[30\sqrt{7}\]                   

    B) \[30\sqrt{3}\]

    C) \[20\sqrt{6}\]                   

    D) \[25\sqrt{2}\]

    Correct Answer: A

    Solution :

    Key Idea Resultant of two forces \[P\] and \[Q\] making an angle \[\alpha \] with each other, is                 \[R=\sqrt{{{P}^{2}}+{{Q}^{2}}+2PQ\cos \alpha }\] Since, forces of magnitude \[30,\,\,60\] and \[P\] are in equilibrium, then magnitude of \[P\] is equal to the magnitude of resultant of forces of magnitude \[30\] and\[60\]. \[\therefore \]  \[P=\sqrt{{{(30)}^{2}}+{{(60)}^{2}}+2(30)(60)\cos {{60}^{o}}}\]                    \[=\sqrt{900+3600+3600\times \frac{1}{2}}\]                    \[=\sqrt{4500+1800}=\sqrt{6300}\]                    \[=30\sqrt{7}\]


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