A) \[30%\]
B) \[3%\]
C) \[1%\]
D) \[10%\]
Correct Answer: B
Solution :
\[''10\]volume\[{{H}_{2}}{{O}_{2}}''\] means \[1\,\,mL\] of its solution on decomposition at\[NTP\], give \[10\,\,mL\] oxygen gas. Volume of oxygen formed from \[100\,\,mL\] of solution at\[NTP=1000\,\,mL\], \[\underset{\begin{smallmatrix} 2\,\,mol \\ 2\times 34\,\,g \end{smallmatrix}}{\mathop{2{{H}_{2}}{{O}_{2}}}}\,\xrightarrow[{}]{{}}2{{H}_{2}}O+\underset{\begin{smallmatrix} 1\,\,mol \\ 22400\,\,mL \end{smallmatrix}}{\mathop{{{O}_{2}}}}\,\] \[\because \]\[22400\,\,m\,\,L\,\,{{O}_{2}}\] formed at \[NTP\] by decomposition of.\[68\,\,g\,\,{{H}_{2}}{{O}_{2}}\]. \[\therefore \]\[1mL\,\,{{O}_{2}}\] formed at \[NTP\] from\[\frac{68}{22400}g\]of\[{{H}_{2}}{{O}_{2}}\] \[\therefore \]\[1000\,\,mL\,\,{{O}_{2}}\]formed at \[NTP\] from \[\frac{68\times 1000}{22400}g\,\,{{H}_{2}}{{O}_{2}}=3.035\,\,g\,\,{{H}_{2}}{{O}_{2}}\] So, concentration of \[''10\]volume\[{{H}_{2}}{{O}_{2}}''\] \[=3.0%\]approximately
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