A) \[HCl,\,\,HBr,\,\,HI\]
B) \[HCl,\,\,B{{r}_{2}},\,\,{{I}_{2}}\]
C) \[C{{l}_{2}},\,\,B{{r}_{2}},\,\,{{I}_{2}}\]
D) \[C{{l}_{2}},\,\,HBr,\,\,HI\]
Correct Answer: B
Solution :
\[NaCl+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }NaHS{{O}_{4}}+HCl\uparrow \] \[HCl+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }\text{No}\,\,\text{reaction}\] \[NaBr+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }NaHS{{O}_{4}}+HBr\] \[2HBr+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }B{{r}_{2}}\uparrow +S{{O}_{2}}+2{{H}_{2}}O\] \[NaI+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }NaHS{{O}_{4}}+HI\] \[2HI+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }{{I}_{2}}\uparrow +S{{O}_{2}}+2{{H}_{2}}O\] Hence, the gases released are HC1, Bra and I^.
You need to login to perform this action.
You will be redirected in
3 sec
