A) \[1,\,\,2\]
B) \[5,\,\,1.5\]
C) \[1.5,\,\,2\]
D) \[2,\,\,3\]
Correct Answer: A
Solution :
For the vertical motion, \[9.81=29.43\sin {{30}^{o}}-\frac{1}{2}\times 9.81\times {{t}^{2}}\] \[[\because \]Vertical displacement\[=(u\sin \alpha )t-\frac{1}{2}g{{t}^{2}}]\] \[\Rightarrow \] \[1=3\sin {{30}^{o}}t-\frac{{{t}^{2}}}{2}\] \[\Rightarrow \] \[{{t}^{2}}-3t+2=0\] \[\Rightarrow \] \[t=1,\,\,2\]
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