A) \[{{(1\times {{10}^{-6}})}^{1/2}}\]
B) \[{{(1\times {{10}^{-6}})}^{1/3}}\]
C) \[{{(0.25\times {{10}^{-6}})}^{1/3}}\]
D) \[{{(0.25\times {{10}^{-6}})}^{1/2}}\]
Correct Answer: C
Solution :
\[PbC{{l}_{2}}\underset{s}{\mathop{P{{b}^{2+}}}}\,+\underset{2s}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{sp}}=(s){{(2s)}^{2}}\] \[1\times {{10}^{-6}}=4{{s}^{3}}\] \[s={{\left( \frac{1}{4}\times {{10}^{-6}} \right)}^{1/3}}\] \[={{(0.25\times {{10}^{-6}})}^{1/3}}\]
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