A) \[60\,\,K\]
B) \[75\,\,K\]
C) \[150\,\,K\]
D) \[225\,\,K\]
Correct Answer: A
Solution :
Here\[{{V}_{1}}=10\,\,L;\,\,{{V}_{2}}=2\,\,L\] \[{{P}_{1}}=1\,\,atm,\,\,{{P}_{2}}=1\,\,atm\] \[{{T}_{1}}=300\,\,K,\,\,{{T}_{2}}=?\] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{1\times 10}{300}=\frac{1\times 2}{{{T}_{2}}}\] \[{{T}_{2}}=\frac{300\times 2}{10}=60\,\,K\]
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