A) impulse
B) change in momentum per unit mass
C) change in \[KE\] per unit mass
D) total change in energy
Correct Answer: C
Solution :
Area of acceleration-displacement curve gives change in \[KE\] per unit mass. \[\frac{1}{2}m({{v}^{2}}-{{u}^{2}})=Fs=\frac{mdv}{dt}\times s\] \[\therefore \] \[\frac{Change\,\,in\,\,KE}{Mas}=\frac{dv}{dt}\times s\]
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