A) angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] is necessarily\[{{90}^{o}}\]
B) angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] can have any value other than\[{{90}^{o}}\]
C) angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] can have any value other than zero and\[{{180}^{o}}\]
D) angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] is either zero or \[{{180}^{o}}\]
Correct Answer: C
Solution :
When a charged particle \[q\] is moving in a uniform magnetic field \[\overset{\to }{\mathop{\mathbf{B}}}\,\] with velocity \[\overset{\to }{\mathop{\mathbf{v}}}\,\] such that angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] be\[\theta \], then due to interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge \[q\] experiences a force which is given by \[F=qvB\sin \theta \] If\[\theta ={{0}^{o}}\]or\[{{180}^{o}}\], then\[\sin \theta =0\] \[\therefore \] \[F=qvB\sin \theta =0\] Since, force on charged particle is non-zero, so angle between \[\overset{\to }{\mathop{\mathbf{v}}}\,\] and \[\overset{\to }{\mathop{\mathbf{B}}}\,\] can have any value other than zero and\[{{180}^{o}}\]. Note: Force experienced by the charged particle is Lorentz force.
You need to login to perform this action.
You will be redirected in
3 sec
