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JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    The equation of the plane containing the line\[\frac{x-{{x}_{1}}}{l}=\frac{y-{{y}_{1}}}{m}=\frac{z-{{z}_{1}}}{n}\]is\[a(x-{{x}_{1}})+b(y-{{y}_{1}})+c(z-{{z}_{1}})=0\], where:

    A) \[a{{x}_{1}}+b{{y}_{1}}+c{{z}_{1}}=0\]

    B) \[al+bm+cn=0\]

    C) \[\frac{a}{l}=\frac{b}{m}=\frac{c}{n}\]

    D)  \[l{{x}_{1}}+m{{y}_{1}}+n{{z}_{1}}=0\]

    Correct Answer: B

    Solution :

    Key Idea: If a plane contains a line, then the DR's of a normal to the plane is perpendicular to the line. If the given plane contains the given line, then normal to the plane, must be perpendicular to the line and the condition for the same is                 \[al+bm+cn=0\]


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