A) \[PC{{l}_{3}}\]
B) \[CO_{3}^{2-}\]
C) \[S{{O}_{2}}\]
D) \[NO_{3}^{-}\]
Correct Answer: A
Solution :
Shape of \[PC{{l}_{3}}\] is pyramidal. In case of\[PC{{l}_{3}}\], three bond pair and one pair electrons is present. Its hybridisation is sp3. Its geometry should be tetrahedral but actually it is pyramidal due to the presence of lone pair of electron.
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